Thanks, Joan, Joe, Mat and Brent. I told Joe I was going to try to use a TV monitor to enlarge the camera’s video output so I could get better focus. It seemed to help. Dave On May 8, 2012, at 1:45 PM, jcarman6@q.com wrote:
Dave, your pictures are the best by far. Excellent detail. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy
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This looks to be annular only by a very small margin. My initial calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show.
If the May 6th full moon was so super, then how come we only get an annular solar eclipse?
This looks to be annular only by a very small margin. My initial
calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy
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If the full moon was at perigee, then about 2 weeks later, the new moon will be at apogee. QED! Wayne Sumner CTE teacher: Astronomy & Engineering Boy's Tennis Coach cell: (801) 721-5852 ________________________________________ From: utah-astronomy-bounces+wsumner=dsdmail.net@mailman.xmission.com [utah-astronomy-bounces+wsumner=dsdmail.net@mailman.xmission.com] on behalf of erikhansen@thebluezone.net [erikhansen@thebluezone.net] Sent: Wednesday, May 09, 2012 8:14 AM To: Utah Astronomy Subject: Re: [Utah-astronomy] Annular but not by much
If the May 6th full moon was so super, then how come we only get an annular solar eclipse?
This looks to be annular only by a very small margin. My initial
calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy
Send messages to the list to Utah-Astronomy@mailman.xmission.com
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_______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy Send messages to the list to Utah-Astronomy@mailman.xmission.com The Utah-Astronomy mailing list is not affiliated with any astronomy club. To unsubscribe go to: http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy Then enter your email address in the space provided and click on "Unsubscribe or edit options".
This morning's calculations were made in a hurry, and I mistook minutes of arc for seconds of arc. The ring will actually have a thickness of 15.75 seconds of arc (1/4 minute of arc). That is still pretty small, but larger than my morning erroneous calculation. The solar diameter on the 20th during the eclipse is 31.558 minutes of arc. The ring thickness will be only 0.83% of the diameter. Now for the excuse: I had to hurry off to a class this morning. I must have gotten a bit smarter in the class. This shows the need for peer review. Anyone feel like checking this calculation? From: Brent Watson <brentjwatson@yahoo.com> To: Utah Astronomy <utah-astronomy@mailman.xmission.com> Sent: Wednesday, May 9, 2012 7:46 AM Subject: [Utah-astronomy] Annular but not by much This looks to be annular only by a very small margin. My initial calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy Send messages to the list to Utah-Astronomy@mailman.xmission.com The Utah-Astronomy mailing list is not affiliated with any astronomy club. To unsubscribe go to: http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy Then enter your email address in the space provided and click on "Unsubscribe or edit options".
I've also been wondering how thick the ring will be. Your numbers seem to correlate to the number on the NASA map called Magnitude; I am assuming that is the percentage area that is covered? For Knarraville it's 0.967. If that is indeed for the area then then diameter would be the square root of that, or 0.983, correct? So 1.7% is uncovered and the ring thickness is half that, or about the number you give. However, on the USNO site they have a number called Obscuration, which sounds like the right number, and for Cedar City it is 87.3%. They don't have Knarraville, but they also have the same Magnitude number for Cedar City that the NASA site has, 0.963. So which is it? There's quite a big difference there. If the Magnitude was for the diameter then the area would be 93.5%, so that's not it. On Wed, May 9, 2012 at 3:51 PM, Brent Watson <brentjwatson@yahoo.com> wrote:
This morning's calculations were made in a hurry, and I mistook minutes of arc for seconds of arc. The ring will actually have a thickness of 15.75 seconds of arc (1/4 minute of arc). That is still pretty small, but larger than my morning erroneous calculation. The solar diameter on the 20th during the eclipse is 31.558 minutes of arc. The ring thickness will be only 0.83% of the diameter.
Now for the excuse: I had to hurry off to a class this morning. I must have gotten a bit smarter in the class. This shows the need for peer review. Anyone feel like checking this calculation?
From: Brent Watson <brentjwatson@yahoo.com> To: Utah Astronomy <utah-astronomy@mailman.xmission.com> Sent: Wednesday, May 9, 2012 7:46 AM Subject: [Utah-astronomy] Annular but not by much
This looks to be annular only by a very small margin. My initial calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy
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Turns out magnitude is the fraction of the diameter that is covered. The strange thing is that other eclipse sites, including another NASA page, give the magnitude for Cedar City as 0.934, which matches the 87.3% area obscuration figure. Now, it turns out 0.934 correlates to an unobscured diameter exactly twice that of 0.967. So what is the correct number? On Wed, May 9, 2012 at 6:22 PM, Craig Smith <cs2560@gmail.com> wrote:
I've also been wondering how thick the ring will be. Your numbers seem to correlate to the number on the NASA map called Magnitude; I am assuming that is the percentage area that is covered? For Knarraville it's 0.967. If that is indeed for the area then then diameter would be the square root of that, or 0.983, correct? So 1.7% is uncovered and the ring thickness is half that, or about the number you give.
However, on the USNO site they have a number called Obscuration, which sounds like the right number, and for Cedar City it is 87.3%. They don't have Knarraville, but they also have the same Magnitude number for Cedar City that the NASA site has, 0.963.
So which is it? There's quite a big difference there. If the Magnitude was for the diameter then the area would be 93.5%, so that's not it.
On Wed, May 9, 2012 at 3:51 PM, Brent Watson <brentjwatson@yahoo.com>wrote:
This morning's calculations were made in a hurry, and I mistook minutes of arc for seconds of arc. The ring will actually have a thickness of 15.75 seconds of arc (1/4 minute of arc). That is still pretty small, but larger than my morning erroneous calculation. The solar diameter on the 20th during the eclipse is 31.558 minutes of arc. The ring thickness will be only 0.83% of the diameter.
Now for the excuse: I had to hurry off to a class this morning. I must have gotten a bit smarter in the class. This shows the need for peer review. Anyone feel like checking this calculation?
From: Brent Watson <brentjwatson@yahoo.com> To: Utah Astronomy <utah-astronomy@mailman.xmission.com> Sent: Wednesday, May 9, 2012 7:46 AM Subject: [Utah-astronomy] Annular but not by much
This looks to be annular only by a very small margin. My initial calculations show the the uncovered disk of the sun will be a ring only 1/4 second of arc thick. Does this jive with other's calculations? If this is correct, it will be very interesting to see what that small amount of sunlight will do to destroy the view of the corona and prominences. If anything is visible, it will be only fleeting. Perhaps Baily's Beads will be the star of the show. _______________________________________________ Utah-Astronomy mailing list http://mailman.xmission.com/cgi-bin/mailman/listinfo/utah-astronomy
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participants (6)
-
Brent Watson -
Craig Smith -
Dave Gary -
erikhansen＠thebluezone.net -
jcarman6＠q.com -
Wayne Sumner