Re: [math-fun] Fast factoring ??
17 Dec
2008
17 Dec
'08
4:38 p.m.
At 01:27 PM 12/17/2008, Fred lunnon wrote:
On 12/17/08, rwg@sdf.lonestar.org <rwg@sdf.lonestar.org> wrote:
... Thereby reenacting one of my favorite denestings:
1/5 3/5 3/5 2/5 1/5 2/5 3/5 1/5 1/3 - 2 3 + 2 3 + 3 + 2 (3 - 2 ) = ------------------------------------- , 2/3 5
a major simplification that looks anything but.
Indeed!
u := 3^(1/5); v := 2^(1/5); w := 5^(1/3); l := (u^3 - v)^1/3;
Presumably you meant to write l := (u^3 - v)^(1/3); which would account for the difference.
r := (u + v^2 - v*u^3 + v^3*u^2)/w^2; evalf(l - r); # -.6607822845 ?!
-- Fred W. Helenius fredh@ix.netcom.com
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