Re: [math-fun] non-square products of squares?
This really is fascinating. I've been trying to follow along with Gap, and I ran into a problem because it takes about five or ten minutes to find all the elements of Aut(2^4). I kept trying to figure out what was wrong, where if I waited I would have had it. So now I can calculate semidirect products 2^4:3[h], where h is a homomorphism from 3 to Aut(2^4), and there are the three you promised: The canonical 2^4:3, the direct product 2^4x3, and... well, one that's halfway in between. I don't know if it's worth giving it a special name. Anyway, I still haven't found any group with a greater proporition of (a,b,ab)=(square,square,nonsquare) than 1/6, except for the 5/24 we get from 2^4:3. In fact, the proportion seems to go down, so perhaps 2^4:3 is unique. I have no idea how one might prove it, though. Here's a poser that came up while I was writing the code to search for nonsquare products. Can it ever happen that (a,b,ab,ba)=(square,square,square,nonsquare)? I can prove it's impossible for finite groups, but what about infinite? Dan
On Fri, 26 Sep 2003, Dan Hoey wrote: >
Here's a poser that came up while I was writing the code to search for nonsquare products. Can it ever happen that (a,b,ab,ba)=(square,square,square,nonsquare)? I can prove it's impossible for finite groups, but what about infinite?
It can't happen, because ba is conjugate to ab, and so if one is a square, so is the other. John Conway
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John Conway