It might be an advantage to have bosons (vs. fermions), where they can all be in the ground state at the same time. So, no extra energy in the mass calculation from being in a higher energy state. This ignores possible interaction energy, though, which is what you are asking. -----Original Message----- From: math-fun [mailto:math-fun-bounces@mailman.xmission.com] On Behalf Of Henry Baker Sent: Monday, June 23, 2014 8:54 PM To: math-fun@mailman.xmission.com Subject: [EXTERNAL] [math-fun] Bozonic boson question "An important characteristic of bosons is that their statistics do not restrict the number that can occupy the same quantum state" https://en.wikipedia.org/wiki/Boson Ok, suppose that I want to _weigh_ one boson. I guess that most bosons are pretty light, so I'll have to weigh a bunch of identical bosons (in "the same" quantum state) & divide by their number. Q: Does this work? Is there any additional energy required to hold them together that would show up as additional mass? Or does an individual boson weigh more singly than when together in "the same" quantum state? How big is the biggest boson, anyway? _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun