Re: [math-fun] geometry puzzle

Actually, it's easy to do for the regular hexagon, so the last sentence should probably read "n = 5 and n >= 7".

It can be done for any n = 6m, by the following procedure: Choose any six vertices, which themselves form a regular hexagon. Label them, in cyclic order, ABCDEF. Reflect the polygonal arc AB in the line BF to obtain a congruent polygonal arc OB, and repeat for all cyclic permutations. We now have six pieces with bilateral symmetry, which can each be subdivided into two congruent pieces. Sincerely, Adam P. Goucher