Waow, yes, that's it, wonderful work, Hans ! à+ É. Catapulté de mon aPhone
Le 13 déc. 2019 à 16:30, Hans Havermann <gladhobo@bell.net> a écrit :
HH: "The odds of picking at random the four letters F, O, U, R in this sentence and in that order are one out of one hundred twenty-seven thousand seven hundred seventy-six." If the probability is 4*11*6*9/132^4 ...
EA: ... aren't the odds 4*11*6*9/(132*131*130*129) ? [brackets added]
OK. Second attempt: "The odds of randomly picking four letters from this statement and having them be F, O, U, and R, are two out of two hundred nineteen thousand six hundred eighty-seven."
Letter count = 132. F count = 5. O count = 11. U count = 6. R count = 8.
5*11*6*8/(132*131*130*129) = 2/219687
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