6 Jun
2016
6 Jun
'16
7:07 a.m.
On 2012-09-06 01:21, Dan Asimov wrote:
Yes, Adam, this is exactly the unique solution (up to similarity) known to date, according to what I read.
--Dan
On 2012-09-05, at 7:07 AM, Adam P. Goucher wrote:
Dan Asimov wrote:
Find a finite subset of the plane such that for any two of its points the perpendicular bisector of the segment connecting them passes through exactly two points of the set.
To avoid spoilers (and for brevity), I'll give my points as the roots of a polynomial over the complex numbers:
z^8 + (6 + 4 Sqrt[3]) z^4 - (7 + 4 Sqrt[3]) = 0.
Dan, is this the original solution?
A tidy similarity being -7 + 4 Sqrt[3] + (6 - 4 Sqrt[3]) x^4 + x^8 = 0. Dan, how about revealing your "obscure source"? --rwg