9 Jan
2003
9 Jan
'03
8:10 a.m.
Kanada used a different formula. See my note, which I mentioned in my previous message. DHB As far as I see the page http://www.sciencenews.org/20021214/mathtrek.asp doesn't say that Kanada actually used pi = 16 arctan(1/5) - 4 arctan(1/239) It only says he used two different _formulas_ (unclear even whether arctan-type). http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun