8 Jun
2011
8 Jun
'11
1:17 p.m.
On Wed, Jun 8, 2011 at 12:07 PM, Eugene Salamin <gene_salamin@yahoo.com> wrote:
In the ring Z[i], the units (divisors of 1) are +1, -1, +i, -i. Thus if d is a divisor of 3+i, so are -d, id, -id. In taking the sum of divisors, how do you make a canonical choice among the associates of each divisor?
First quadrant. -- Mike Stay - metaweta@gmail.com http://www.cs.auckland.ac.nz/~mike http://reperiendi.wordpress.com