8 Jan
2007
8 Jan
'07
3:38 p.m.
That second case should of course be a(m) = k*2^m for m < M, 0 thereafter. Franklin T. Adams-Watters -----Original Message----- From: franktaw@netscape.net ... (This argument does not apply to the case n = 1, where the only solutions are a(m) = k*2^m and a(m) = k^2^m for m < M, 0 thereafter.) ... ________________________________________________________________________ Check Out the new free AIM(R) Mail -- 2 GB of storage and industry-leading spam and email virus protection.