8 Jan
2013
8 Jan
'13
4:30 p.m.
I hadn't know about Meissner tetrahedra, but was vaguely aware that there were no known 3D analogues of Reuleaux triangles that have constant width. QUESTION: Has anyone proved that a 3D shape of constant width *cannot* have the symmetry of the tetrahedron? (Meaning no additional symmetries, either.) --Dan On 2013-01-08, at 3:12 AM, Tom Karzes wrote:
I wonder if Meissner tetrahedra (true constant width) would work better or worse than Reuleaux tetrahedra (approximate constant width) for this purpose.