[math-fun] binomial^n = binomial

Are there any more of these? (2^(2/3) - 1)^4 = 12*2^(1/3) - 15, (10^(1/3) - 1)^5 = 99 - 45*10^(1/3), (5^(1/3) - 2^(1/3))^6 = 63*2^(2/3)*5^(1/3) - 171 . --rwg