19 Jan
2020
19 Jan
'20
12:57 a.m.
Hi, a [n+1]=2^(2*n+3)*(1-(1-a [n]/2^(2*n+2))^(1/2)) a [0]=4 ; n----> infinity a [n]----> Pi^2 We see that: 1-a [n]/2^(2*n+2)=(1-a [n+1]/2^(2*n+3))^2 Best regards Envoyé depuis Yahoo Mail pour Android