30 Jan
2020
30 Jan
'20
5:42 p.m.
On 31 Jan 2020 at 0:18, Gareth McCaughan wrote:
On 30/01/2020 23:16, Cris Moore via math-fun wrote:
This is too easy, but one could also consider the fact that any polynomial of odd degree (and real coefficients) has at least one real root...
Is there a parity-based proof of that that isn't strictly inferior to "f(-large) and f(+large) are large and of opposite sign, so by the intermediate value theorem there's a root somewhere between"?
Is it not sufficient to show that complex roots always come in pairs, and so when you've exhausted all the complex roots there must be [at least] one more? /Bernie\ Bernie Cosell bernie@fantasyfarm.com -- Too many people; too few sheep --