Re: [math-fun] Cube root of a complex number

Quoting Dan Asimov <dasimov@earthlink.net>:

It's a pleasant exercise to calculate the square root of the complex number a + bi directly (without making use of polar form or trig functions).

What's even more pleasant (for purposes of numerical analysis) is that it can be done only using square roots of positive real numbers. Even if a = -1 and b=0. ------------------------------------------------- www.correo.unam.mx UNAMonos Comunicándonos