That's much better; my pdf viewer didn't render anything but the three circles. On Thu, Nov 12, 2009 at 10:16 AM, Henry Baker <hbaker1@pipeline.com> wrote:
It is indeed a fractal. Look more closely -- there are individual dots.
Try printing this Postscript version, which actually computes the fractal inside your printer using embedded Postscript code:
http://home.pipeline.com/~hbaker1/sigplannotices/sigcol07.ps.gz
(".gz" means "gzip"; I believe that "7-zip" can ungzip this file for you.
There is a small program called "PrintFile" which can send Postscript files on Windows to your Postscript printer.
If worst comes to worst, install Ghostscript on your computer & look at the output that way.
At 10:06 AM 11/12/2009, Mike Stay wrote:
Figure three seems wrong in this rendering--shouldn't it be a fractal?
On Thu, Nov 12, 2009 at 9:47 AM, Henry Baker <hbaker1@pipeline.com> wrote:
That was my paper!
http://home.pipeline.com/~hbaker1/sigplannotices/sigcol07.pdf
At 09:19 AM 11/12/2009, mcintosh@servidor.unam.mx wrote:
Re: [math-fun] Cube root of a complex number
somewhat tangential to the original question, Möbius transformations map three points into three points. So, why not map the three roots of the cubic into the three complex roots of unity? You only get to use the coefficients of the polynomial.
I recall a paper in an ACM journal humorously dated March 32 some years ago where someond did that; I don't remember if the solution was relevant to the present inquiry.
-- Mike Stay - metaweta@gmail.com http://math.ucr.edu/~mike http://reperiendi.wordpress.com
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-- Mike Stay - metaweta@gmail.com http://math.ucr.edu/~mike http://reperiendi.wordpress.com