Re: [math-fun] Last 4 digits of S sum up to a square

EA: "... the start 0, 1, 2, 6, 7, 12 is not in the OEIS either ..." I don't like the fact that 0+1+2 is not a square. I would start it 0, 1, 3, 5, 7, 13, ... When S has exhausted its supply of integers less than 1000 (994 at position 1193), subsequent terms are determined by the final four digits of the number itself. This is fairly predictable and somewhat boring. Here is a graph: http://chesswanks.com/seq/last4digits