22 Jun
2010
22 Jun
'10
1:35 a.m.
The second identity should be Th2(0,sqrt(q)) * Th3(0,sqrt(q)) == 2 * eta(q)^4 / eta(sqrt(q))^2 (note squared denominator in rhs.) * Bill Gosper <billgosper@gmail.com> [Jun 21. 2010 11:29]:
Arcsinh of (the same) four thetas, twice. http://gosper.org/R-R CF.pdf Anyone have a shorter expression? Can anyone convince Mma to Series the rhs? --rwg _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun