I didn't follow this. Maybe you're talking about the triangle being attached to the opposite side? It's supposed to be attached to the adjacent side in the problem. Here's what the six sided figure looks like (ASCII art warning) after cutting out the triangle and connecting it to an adjacent side. ************ * * * * * * * * * * * * * * * Now the problem is to cut this 6 sided figure into two pieces that can be reassembled into a shape congruent to the original square. Thane Plambeck 650 321 4884 office 650 323 4928 fax http://www.qxmail.com/home.htm ----- Original Message ----- From: "Mike Stay" <staym@datawest.net> To: <math-fun@mailman.xmission.com> Sent: Wednesday, November 13, 2002 2:00 PM Subject: Re: [math-fun] A problem from the files of David Klarner I wrote:
There's a simple extension of the trivial case you mentioned: Let E,F be the midpoints of AB, CD respectively. Then you can cut the rectangle AEFD lengthwise. I suspect there's a way to cut it where you turn one of the pieces over...
That last sentence should be
I suspect there's a way to cut it [the figure, not necessarily the rectangle] where you turn one of the pieces over... -- Mike Stay staym@datawest.net
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