I wrote:
I actually know two different proofs of the result. One follows the approach to such problems that I learned from George Hart (see his email to math-fun from October 18), and the other follows the approach I learned from Warren Smith (see my email to math-fun from October 19). If you look at their solutions to the random-slices-of-a-cube problem you might be inspired, as I was, to see how to solve the random-intersecting- parallelograms-puzzle.
George's method can also be used to prove that if you take a random nonempty intersection of a regular hexagon with a translate of itself, the expected number of sides is exactly 5.
Hint: instead of counting sides, count vertices. I'll sketch the proof tomorrow or Wednesday, if nobody beats me to it. Anyway, two days have passed since I posted the puzzle, so I think it's
appropriate to have an unbridled conversation, with or without spoilers.
Let me say, by way of motivation, that the "George-style" proof is really sweet. You'll feel good when you find it. Jim