26 Sep
2018
26 Sep
'18
6:26 p.m.
Brent Meeker <meekerdb@verizon.net> wrote:
What you do is iterate. You can take three points and using spherical geometry determine a radius and a center.
But any three points that obey the triangle inequality are compatible with any radius of curvature whatsoever. (Except for a radius less than that which makes them coplanar with the center of the circle they're on.)