16 Jul
2017
16 Jul
'17
7:16 p.m.
Out[1028]= Sum[((-1)^n*QPolyGamma[0, -(Log[-(n/2)]/Log[2]), 1/2])/ n, {n, 1, Infinity}] == (-1 + EulerGamma - Log[2])*Log[2] In[1029]:= N@% Out[1029]= True