8 Feb
2012
8 Feb
'12
7:46 p.m.
According to what I've read, Fermat posed this problem to Mersenne in 1943. This puzzle is intended for people who haven't seen the solution already: Find a primitive Pythagorean triple a^2 + b^2 = c^2 such that both a+b and c are each square numbers. (Please e-mail your answers straight to me so they don't keep others from solving this.) --Dan ________________________________________________________________________________________ It goes without saying that .