As has been mentioned in this thread, at the pressures in a neutron star a neutron is stable relative to a proton + electron. Electrostatic force pulls e + p => n together long before they can separate gravitationally. --R
--I quote from "earlier in thread" post by E.Salamin: So the electron density is 4% of the neutron density, and by electrical neutrality the same holds for the proton density. Note that the electron density scales as the square of the neutron density, as long as the neutrons remain non-relativistic. So if we assume instead a neutron density of 10^44 m-3, the electron density will be 0.4% of the neutron density... WDS: If Salamin is anywhere near correct there will be plenty of free protons & electrons; and they presumably will be distributed in a near min-energy manner, which means separated with the protons nearer the bottom. The distribution will be such that the gravitational forces are exactly balanced by the coulombic forces. This will cause an electric field. If you deny the existence of free protons in the mix, then I guess I'd have to ask: why are you even talking about superconductivity at all? Wouldn't you then deny its existence too?