26 Jan
2018
26 Jan
'18
11:52 a.m.
Hello... p(x)=(1/2^(2/3))*product((cosh(x)^(2/(16*n^2+16*n+3))*cosh((4*n*x)/(4*n+1)))/cosh(((4*n+2)*x)/(4*n+3)),n,1,inf); we have: lim(p(x),x=infinity)=2^(-Pi/4) ; where still under maple: Limit((1/2^(2/3))*product((cosh(x)^(2/(16*n^2+16*n+3))*cosh((4*n*x)/(4*n+1)))/cosh(((4*n+2)*x)/(4*n+3)),n=1..infinity),x=infinity)=1/2^(Pi/4); and Limit((1/2^(2/3))*product((sinh(x)^(2/(16*n^2+16*n+3))*sinh((4*n*x)/(4*n+1)))/sinh(((4*n+2)*x)/(4*n+3)),n=1..infinity),x=infinity)=1/2^(Pi/4); Best regards...