On Tue, Jul 5, 2011 at 6:40 PM, Eugene Salamin <gene_salamin@yahoo.com> wrote:
How does a nonreal number manage to muscle its way into Q(sqrt(3)), a real field?
Sorry; the rule that any post correcting an error must itself contain an error applies here. I meant Q(sqrt(3), i). Andy
-- Gene
________________________________ From: Andy Latto <andy.latto@pobox.com> To: math-fun <math-fun@mailman.xmission.com> Sent: Tuesday, July 5, 2011 3:22 PM Subject: Re: [math-fun] Minsky Harmonic Motion
Q((sqrt(3)) is a field of characteristic 0, but it includes
(sqrt(3) + i)/2, and the twelfth power of this is 1.
Andy
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-- Andy.Latto@pobox.com