My understanding is that there is a lag between the strongest gradient of the gravitational force and the high tides. Below is for Honolulu this coming Valentine's Day. The simple model would predict high tides at roughly noon and at midnight. Coastal features can also complicate things, I believe. Day High Low High Low Moon Sunrise Sunset Fri 14 3:59 AM HST / 1.94 ft 10:39 AM HST / 0.14 ft 4:05 PM HST / 1.09 ft 9:44 PM HST / 0.03 ft Full Moon 7:02 AM HST 6:29 PM HST BC -----Original Message----- From: math-fun-bounces@mailman.xmission.com [mailto:math-fun-bounces@mailman.xmission.com] On Behalf Of Dan Asimov Sent: Tuesday, February 11, 2014 3:35 PM To: math-fun Subject: [EXTERNAL] Re: [math-fun] atomic clocks & gravitational time dilation This explanation from the text Mike sugggests is the same explanation I've long heard from reliable sources: ----- * Water on the side of Earth facing the moon is pulled hardest by the moon's gravity. This causes a bulge of water on that side of Earth. That bulge is a high tide. * Earth itself is pulled harder by the moon's gravity than is the ocean on the side of Earth opposite the moon. As a result, there is bulge of water on the opposite side of Earth. This creates another high tide. * With water bulging on two sides of Earth, there's less water left in between. This creates low tides on the other two sides of the planet. ----- But I'm curious: * Are the tides on the sides of the earth nearest and farthest from the moon symmetrical? * If so, why (since the reasons given for those tides are different) ? --Dan On 2014-02-11, at 2:17 PM, Mike Stay wrote:
On Tue, Feb 11, 2014 at 2:41 PM, Bill Gosper <billgosper@gmail.com> wrote:
PS, has anyone ever found a correct explanation of tides in a middle or high school text?
http://www.ck12.org/earth-science/Tides/lesson/Tides-Basic/
-- Mike Stay - metaweta@gmail.com http://www.cs.auckland.ac.nz/~mike http://reperiendi.wordpress.com
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