Re: [math-fun] q. re Farey-ish fractions with weighted mediants

I don't see where the restriction to odd denominators comes from. --Rich

Maybe I missed the drift of the conversation, but I thought the topic was my weighted-mediants version of the Stern-Brocot tree, starting with 0/1 and 1/1. If a/b and c/d have odd denominators, so must (2a+c)/(2b+d) and (a+2c)/(b+2d). (This doesn't apply to the numerators, since we start with 0/1 which has even numerator.) Jim