[math-fun] Did any of you integrate √tan in freshman calculus?

In[38]:= Integrate[√Tan[x], x] Out[38]= 2/3 Hypergeometric2F1[3/4, 1, 7/4, -Tan[x]^2] Tan[x]^(3/2) In[39]:= FunctionExpand@% Out[39]= 2/3 Tan[x]^( 3/2) (-((3 ArcTan[(-Tan[x]^2)^(1/4)])/(2 (-Tan[x]^2)^(3/4))) + ( 3 ArcTanh[(-Tan[x]^2)^(1/4)])/(2 (-Tan[x]^2)^(3/4))) I'm pretty sure this would've left me some PTSD. And again later with Macsyma's Risch implementation. I suspect a conspiracy to hide this from emotionally vulnerable undergrads. —rwg