25 Aug
2013
25 Aug
'13
9:51 a.m.
There are *three* (base-ten) 38-digit squares that can be split (somewhere) so that (the difference of the two parts)^2 is the original number. One of them is 3636363636363636365^2: Square: 13223140495867768604958677685950413225 Split: 1322314049586776860'4958677685950413225 Subtract: abs(1322314049586776860-4958677685950413225) = 3636363636363636365 What are the other two solutions?