30 Oct
2003
30 Oct
'03
9:23 a.m.
Haven't looked at all today's 50 messages yet, but 3 have addressed this topic. Isn't the general solution x = k(ad + bc), y = kbd ?? R. On Wed, 29 Oct 2003, John Conway wrote:
On Wed, 29 Oct 2003, Jon Perry wrote:
This may be completely dumb, but is it always possible to solve x/y = a/b + c/d, where all algebraic quantities are positive integers, for all x and y?
How about a=x, b=y, c=0, d=1 ? John Conway
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