17 May
2008
17 May
'08
11:31 a.m.
Here's a question that probably has an obvious answer, but I have to ask it: Does the Fibonacci multiplication (which Knuth denotes with just a circle: x o y) have a continuous extension to the positive reals that remains commutative and associative ? --Dan P.S. All definitions are here: http://en.wikipedia.org/wiki/Zeckendorf's_theorem _____________________________________________________________________ "It don't mean a thing if it ain't got that certain je ne sais quoi." --Peter Schickele