You'll need to do something about restricting the values used by the malicious replacer. Otherwise you could take them all linearly independent over Q. Victor On Mon, Jul 2, 2012 at 9:35 PM, Warren Smith <warren.wds@gmail.com> wrote:
On 7/2/12, Warren Smith <warren.wds@gmail.com> wrote:
Now consider the set of all vectors in n dimensions, each of whose entries lies in the real closed interval [-1,+1]. This is a solid hypercube. An evil child maliciously replaces some subset of the vector entries by reals of smaller absolute value.
--and I should have said "...and of the same sign, or 0."
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