Re: [math-fun] Fwd: 2015 with the other six digits

Zack Chroman (via Bill Gosper):

Using 1,2,3,4,5,6,7,8,9 in that order (with concatenated digits), it's possible up to 6964. I have some Mathematica code for this because of this problem <https://projecteuler.net/problem=259>, but it's being annoying when I try to get it to go 10-1 instead of 1-9.

I should point out that in my previous reply, which had 2102 as unreachable (using, in order, 10-1), I did NOT consider parentheses, which IS allowable in problem 259.