Which reminds me of a question I had. During a rainstorm/snowstorm, how does visibility relate to the density of liquid water/snow in the air?
-----Original Message----- From: math-fun [mailto:math-fun-bounces@mailman.xmission.com] On Behalf Of Hans Havermann Sent: Monday, January 26, 2015 5:30 PM To: math-fun Subject: Re: [math-fun] Let it snow
My guess is that these data points are strictly inches of liquid water. I think an approximate conversion to inches of snow would have you multiply (depending on the snow type) by anywhere from 8 to 14.
On Jan 26, 2015, at 4:33 PM, James Propp <jamespropp@gmail.com> wrote:
Does "0.2 in/hr" mean one-fifth of an inch per hour? It seems to me, given the severity of the current blizzard, they must mean something closer to two inches per hour.
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