From this reference
http://www.aei.mpg.de/~schutz/download/lectures/AzoresCosmology/Schutz.Azore... the flux (power per unit area) carried by a gravitational wave of frequency f and strain h is F = (pi/4) (c^3/G) f^2 h^2 = (3.2 mW/m^2) (h / 1e-22)^2 (f / 1 kHz)^2. At the peak of the recently detected wave, h = 1e-21, f = 100 Hz, so that F[peak] = 3.2 mW/m^2. Note that strain is dimensionless. Unlike the situation in an elastic solid, the gravitational wave flux is necessarily frequency dependent, since a static strain is merely the use of a different scale for the x, y, and z axes, and this is just flat space. The constant c^3 / G = (3e8 m s^-1)^3 / (6.67e-11 kg^-1 m^3 s^-2) = 4.05e35 W m^-2 Hz^-2. Since general relativity is classical, Planck's constant can't appear, and the constant must be constructed from G and c only. If the frequency dependence were any power of f other than f^2, this would not be possible. About 2% of the Sun's luminosity is emitted as neutrinos. That's 20 mW/m^2 at Earth. -- Gene From: Keith F. Lynch <kfl@KeithLynch.net> To: math-fun@mailman.xmission.com Sent: Sunday, February 21, 2016 12:59 PM Subject: [math-fun] Maps from earthshine? (One final aside on moonlight and gravitational waves: Has anyone else noticed that the peak flux of the gravitational wave event, GW150914, on Earth was seven times the flux of the light of the full Moon? If it was visible light, you could not only have seen it, but could have read by its light. LIGO isn't really very sensitive!)