1 Mar
2013
1 Mar
'13
12:17 p.m.
Both of these are incredibly beautiful identities, especially if true. Which, given their source, seems very likely. If anyone has proved this already, my guess is it would be Euler. Have his complete works been collected yet, and even better, are they freely available in English translation on the Web? --Dan On 2013-02-27, at 3:05 PM, Bill Gosper wrote:
Sum[2^k/(1 + z^2^k), {k, -Infinity, Infinity}] == 1/Log[z] Can somebody tell me where? --rwg And, as Neil empiricizes, Sum[2^k/(1 + z^2^k), {k, 0, Infinity}] == 1/(z-1) _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun