this one is bound to be part of jim muth classic, this type go well with presentatin...i find the par i loose..passing a 1000 make me count...time to go and buy another powerball -- most attached file or result are positively balance at :https://sites.google.com/site/sinpix12823fractal/ empty_to_full { ; 04_07_2012 ; easy_wezo reset=2004 type=formula formulafile=2012_7.frm formulaname=difficile center-mag=+0.02249649165000000/+1.15343537500000000/155.1729/0.9996 params=1/1/1/1/2/0 maxiter=200000 inside=0 colors=000<12>000000000<3>000<8>U0MX0O_0Rc0Tf0W<2>q0cu0fz0j<2>z00<3>zz0<\ 3>0z0<3>0zz<2>0GzVVz<3>zVz<3>zVV<3>zzV<3>VzV<3>Vzz<2>Vbzhhz<3>zhz<3>zhh<\ 3>zzh<3>hzh<3>hzz<2>hlz00S<3>S0S<3>S00<3>SS0<3>0S0<3>0SS<2>07SEES<3>SES<\ 3>SEE<3>SSE<3>ESE<3>ESS<2>EHSKKS<2>QKSSKSSKQSKOSKMSKK<2>SQKSSKQSKOSKMSKK\ SK<2>KSQKSSKQSKOSKMS00G<3>G0G<3>G00<3>GG0<3>0G0<3>0GG<2>04G88G<2>E8GG8GG\ 8EG8CG8AG88<2>GE8GG8EG8CG8AG88G8<2>8GE8GG8EG8CG8AGBBG<2>FBGGBGGBFGBDGBCG\ BB<2>GFBGGBFGBDGBCGBBGB<2>BGFBGGBFGBDGBCG000<6>000 } frm:difficile{;Sebastien a=real(p1*imag(p1)),b=real(p2*0.555555556),d=real(p3) z=b^2+a-d,c=pixel^p3: z=z^2+c |z|<74 }