Diamond and square
Today image is a ritch mix of square circle, give a particular result. you can view it at https://sites.google.com/site/sinpix12823fractal/ START PARAMETER FILE================================ Diamond_Square { reset=2004 type=formula formulafile=2012_3.frm formulaname=vil function=cosh corners=-3.238748/5.241252/-0.04978297/6.310217 params=0.1/0.1/1/1000 float=y maxiter=2000 inside=fmod potential=120/200/4 colors=000<3>0Mm0Sz0Sw<7>8KY9JVAIS<2>DFIEEEHHH<8>777666555<3>000<8>KK0MM\ 0OO0<3>YY0<3>HH0DD0990550000<8>WWL__NccP<3>rrZ<3>mmakkbjjbhhcggdeee<8>fp\ fgqggrg<3>hxh<6>gngfmffkf<2>fgfeeecde<7>HQYFOXCMW<3>0ES07SEES<3>SES<3>SE\ E<3>SSE<3>ESE<3>ESS<2>EHSKKS<2>QKSSKSSKQSKOSKMSKK<2>SQKSSKQSKOSKMSKKSK<2\
KSQKSSKQSKOSKMS00G<3>G0G<3>G00<3>GG0<3>0G0<3>0GG<2>04G88G<2>E8GG8GG8EG8\ CG8AG88<2>GE8GG8EG8CG8AG88G8<2>8GE8GG8EG8CG8AGBBG<2>FBGGBGGBFGBDGBCGBB<2\ GFBGGBFGBDGBCGBBGB<2>BGFBGGBFGBDGBCG000<6>000 }
frm:vil{;sinpix a=real(p1) b=real(p2) c=imag(p1) d=imag(p2) e=sin(a/b) f=sin(c/d) z=fn1(pixel): q=1/z^e r=1/z^f z=tan(z*q)+sin(z^r)-z^(a/b) |z|<10 } END PARAMETER FILE============================== START PARAMETER FILE================================ Diamond_Square { reset=2004 type=formula formulafile=2012_3.frm formulaname=vil function=cosh corners=-3.238748/5.241252/-0.04978297/6.310217 params=0.1/0.1/1/1000 float=y maxiter=2000 inside=fmod potential=120/200/4 colors=000<3>0Mm0Sz0Sw<7>8KY9JVAIS<2>DFIEEEHHH<8>777666555<3>000<8>KK0MM\ 0OO0<3>YY0<3>HH0DD0990550000<8>WWL__NccP<3>rrZ<3>mmakkbjjbhhcggdeee<8>fp\ fgqggrg<3>hxh<6>gngfmffkf<2>fgfeeecde<7>HQYFOXCMW<3>0ES07SEES<3>SES<3>SE\ E<3>SSE<3>ESE<3>ESS<2>EHSKKS<2>QKSSKSSKQSKOSKMSKK<2>SQKSSKQSKOSKMSKKSK<2\
KSQKSSKQSKOSKMS00G<3>G0G<3>G00<3>GG0<3>0G0<3>0GG<2>04G88G<2>E8GG8GG8EG8\ CG8AG88<2>GE8GG8EG8CG8AG88G8<2>8GE8GG8EG8CG8AGBBG<2>FBGGBGGBFGBDGBCGBB<2\ GFBGGBFGBDGBCGBBGB<2>BGFBGGBFGBDGBCG000<6>000 }
frm:vil{;sinpix a=real(p1) b=real(p2) c=imag(p1) d=imag(p2) e=sin(a/b) f=sin(c/d) z=fn1(pixel): q=1/z^e r=1/z^f z=tan(z*q)+sin(z^r)-z^(a/b) |z|<10 } END PARAMETER FILE==============================
participants (1)
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Sebastien Helie