FOTD -- August 23, 2012 (Rating 6) Fractal visionaries and enthusiasts: To produce today's little masterwork, I took the expression Z^(sqrt(2))+C and calculated it 0.707106781 levels up the logarithmic hyperspiral. (The hyperspiral is another name for the hyperladded.) By no strange coincidence, 0.707106781 is the reciprocal of 1.4142135624, the square root of 2. The resulting parent fractal is a monster with more convolutions than a street map of Tokyo. Today's image lies in the Seahorse Valley area of the parent, though one would never guess it by looking at the parent. Rarely have I seen such an obscure Seahorse Valley. The rating of a 6 is a sign that I am not very impressed with the image. We have seen too many similar images over the past 15 years of the FOTD. The name "Square Root Reciprocal" describes the expression that created the image. The calculation time of 3-1/4 minutes is slow, though still faster than yesterday's. Visit the web sites for a speedier way to view the image. View the finished image at: <http://www.crosscanpuzzles.com/Archives.html> A high-definition rendering is at: <http://www.emarketingiseasy.com/TESTS/FOTD/jim_muths_fotd.html> The back images are at: <http://www.Nahee.com/FOTD/> A near perfect day passed by peacefully here at Fractal Central today. The fractal cats heartily approved of the near cloudless skies and temperature of 84F 29C. The humans went through the day with nothing exceptional to report. The next FOTD will be posted in more than an hour but not as much as a week. Until whenever that might be, take care, and it seems we're becoming so frantic to stay healthy that we have forgotten how to live. Jim Muth jimmuth@earthlink.net START PARAMETER FILE======================================= Sqrt_reciprocal { ; time=0:03:15.00 SF5 at 2000MHZ reset=2004 type=formula formulafile=basicer.frm formulaname=MandelbrotBC3 function=cosxx passes=1 center-mag=+0.8559664295/-0.0636040039/13101/1/\ 50/0 params=1.4142135624/0/0.707106781/0 float=y maxiter=3750 inside=0 logmap=146 periodicity=6 colors=000JBKIAII9HH8FG8EF7CE6AE59D57C46B34B33C43C\ 53C63C73C83C93GA6KB9OCCSDEWEH_EKcFNgGPkHSoIVsIXoHW\ lGVhFUeEUaDTZDSVCRSBRPAQL9PI9OE8OB7N76M45L15L4BS6G\ Y8McARiCQoRPjQKeQFaPAYPAUQCPRELSGHTHITJJULKVMLWONW\ QzXRzYTzZVz_Wz_Yz`_za`zbbzbdzcezdgzeizejzZdzTZzMUz\ GOzAJzAIzAIzAHzAHzAGzAGsAFsAFsAFrAErAEqADqADqACzAC\ z99zACzAEzBHzBJzCLzCOzDQzDSzEVzEXz9PzCUzEZzGbVJgaL\ lhFqpJpoNpoQpoUooXoo`ondnngnnknnqppnnnklmhjlehkbgj\ `eiYchVagS`fPZeMXzKVzHUzESzBQz8Oz7Rz4Mz6Nz7Oz8Pz9Q\ zBRzCRzDSzETzGUzHVzIVzJWzLXzMYzNZzOZzQ_nR`oSapTbqY\ etUbqR`nOYkLWzHTzERzBOz4Lz6Mz8MzAMzCMmDMmFMmHMmJMm\ LMmMMmOMmQMmSMmUMmVMmXMmZMm`MmbMmzMEzMDzMCzMBzIBzK\ AzMAzO9zQ9zS8zU8pWmrYms_mtamvcmwecxgcyiczgczeczdcz\ bcz`czczzczzczzczzczzczzczzczzcbzcezcgzcjzclzcozcq\ zcszmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzm\ zzmzzmzzmzzmzzmzzmzzmzzmz } frm:MandelbrotBC3 { ; by several Fractint users e=p1, a=imag(p2)+100 p=real(p2)+PI q=2*PI*fn1(p/(2*PI)) r=real(p2)+PI-q Z=C=Pixel: Z=log(Z) IF(imag(Z)>r) Z=Z+flip(2*PI) ENDIF Z=exp(e*(Z+flip(q)))+C |Z|<a } END PARAMETER FILE=========================================
i call... boro..? shy.... douou like little boy? 2012/8/23 Jim Muth <jimmuth@earthlink.net>
FOTD -- August 23, 2012 (Rating 6)
Fractal visionaries and enthusiasts:
To produce today's little masterwork, I took the expression Z^(sqrt(2))+C and calculated it 0.707106781 levels up the logarithmic hyperspiral. (The hyperspiral is another name for the hyperladded.) By no strange coincidence, 0.707106781 is the reciprocal of 1.4142135624, the square root of 2.
The resulting parent fractal is a monster with more convolutions than a street map of Tokyo. Today's image lies in the Seahorse Valley area of the parent, though one would never guess it by looking at the parent. Rarely have I seen such an obscure Seahorse Valley.
The rating of a 6 is a sign that I am not very impressed with the image. We have seen too many similar images over the past 15 years of the FOTD.
The name "Square Root Reciprocal" describes the expression that created the image.
The calculation time of 3-1/4 minutes is slow, though still faster than yesterday's. Visit the web sites for a speedier way to view the image.
View the finished image at:
<http://www.crosscanpuzzles.com/Archives.html>
A high-definition rendering is at:
<http://www.emarketingiseasy.com/TESTS/FOTD/jim_muths_fotd.html>
The back images are at:
A near perfect day passed by peacefully here at Fractal Central today. The fractal cats heartily approved of the near cloudless skies and temperature of 84F 29C. The humans went through the day with nothing exceptional to report. The next FOTD will be posted in more than an hour but not as much as a week. Until whenever that might be, take care, and it seems we're becoming so frantic to stay healthy that we have forgotten how to live.
Jim Muth jimmuth@earthlink.net
START PARAMETER FILE=======================================
Sqrt_reciprocal { ; time=0:03:15.00 SF5 at 2000MHZ reset=2004 type=formula formulafile=basicer.frm formulaname=MandelbrotBC3 function=cosxx passes=1 center-mag=+0.8559664295/-0.0636040039/13101/1/\ 50/0 params=1.4142135624/0/0.707106781/0 float=y maxiter=3750 inside=0 logmap=146 periodicity=6 colors=000JBKIAII9HH8FG8EF7CE6AE59D57C46B34B33C43C\ 53C63C73C83C93GA6KB9OCCSDEWEH_EKcFNgGPkHSoIVsIXoHW\ lGVhFUeEUaDTZDSVCRSBRPAQL9PI9OE8OB7N76M45L15L4BS6G\ Y8McARiCQoRPjQKeQFaPAYPAUQCPRELSGHTHITJJULKVMLWONW\ QzXRzYTzZVz_Wz_Yz`_za`zbbzbdzcezdgzeizejzZdzTZzMUz\ GOzAJzAIzAIzAHzAHzAGzAGsAFsAFsAFrAErAEqADqADqACzAC\ z99zACzAEzBHzBJzCLzCOzDQzDSzEVzEXz9PzCUzEZzGbVJgaL\ lhFqpJpoNpoQpoUooXoo`ondnngnnknnqppnnnklmhjlehkbgj\ `eiYchVagS`fPZeMXzKVzHUzESzBQz8Oz7Rz4Mz6Nz7Oz8Pz9Q\ zBRzCRzDSzETzGUzHVzIVzJWzLXzMYzNZzOZzQ_nR`oSapTbqY\ etUbqR`nOYkLWzHTzERzBOz4Lz6Mz8MzAMzCMmDMmFMmHMmJMm\ LMmMMmOMmQMmSMmUMmVMmXMmZMm`MmbMmzMEzMDzMCzMBzIBzK\ AzMAzO9zQ9zS8zU8pWmrYms_mtamvcmwecxgcyiczgczeczdcz\ bcz`czczzczzczzczzczzczzczzczzcbzcezcgzcjzclzcozcq\ zcszmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzmzzm\ zzmzzmzzmzzmzzmzzmzzmzzmz }
frm:MandelbrotBC3 { ; by several Fractint users e=p1, a=imag(p2)+100 p=real(p2)+PI q=2*PI*fn1(p/(2*PI)) r=real(p2)+PI-q Z=C=Pixel: Z=log(Z) IF(imag(Z)>r) Z=Z+flip(2*PI) ENDIF Z=exp(e*(Z+flip(q)))+C |Z|<a }
END PARAMETER FILE=========================================
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participants (2)
-
Jim Muth -
Sebastien Helie